0=12x^2-12x-24

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Solution for 0=12x^2-12x-24 equation:



0=12x^2-12x-24
We move all terms to the left:
0-(12x^2-12x-24)=0
We add all the numbers together, and all the variables
-(12x^2-12x-24)=0
We get rid of parentheses
-12x^2+12x+24=0
a = -12; b = 12; c = +24;
Δ = b2-4ac
Δ = 122-4·(-12)·24
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*-12}=\frac{-48}{-24} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*-12}=\frac{24}{-24} =-1 $

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